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32,320 Views • Oct 26, 2024 • Click to toggle off description
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Genre: Education
Uploaded At Oct 26, 2024 ^^
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RYD date created : 2024-11-10T16:40:39.733936Z
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18 Comments
Top Comments of this video!! :3
For this example, [5, 10, 3, 4], we can go to all the houses like this : [10,4,5,3]
4 |
This is my view of this problem approach. We check the value of arr[i] + arr[i+2]. We store in a int variable. Every time we add two array element together we compare it with the int variable. Then the return the largest int value.
4 |
See you do not get the tabulations by examining the recursion trees. You get the tabulations by understanding the problems and a hint that tabulation is going to work.
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Can we do it like this:-
Int maxSum(array){
max=Int_min;
For i to array.size(){
For j=i in range(array.size(),2) {
sum=array[i]+[j];
max=(sum,array);
}
}
return max; }
But it has time complexity of O(n2)😅
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Hello❤
1 |
Yns program
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❤❤❤❤
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buddy we dont ask dynamic question anymore.
5 |
or you could return the greater of even houses versus odd houses, no dynamic programming necessary.
1 |
@GregHogg
4 weeks ago
Master data structures and algorithms for FREE at algomap.io/ :)
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