PokeVideoPlayer v23.9-app.js-020924_
0143ab93_videojs8_1563605_YT_2d24ba15 licensed under gpl3-or-later
Views : 1,828
Genre: Education
License: Standard YouTube License
Uploaded At Oct 24, 2024 ^^
warning: returnyoutubedislikes may not be accurate, this is just an estiment ehe :3
Rating : 5 (0/69 LTDR)
100.00% of the users lieked the video!!
0.00% of the users dislieked the video!!
User score: 100.00- Masterpiece Video
RYD date created : 2024-12-09T23:10:17.121868Z
See in json
Top Comments of this video!! :3
I know this "slight of hand" in a slightly more subtle way.
The beginning is the same up to
a^2 = ab
Then subtract b^2 on both sides
a^2 - b^2 = ab - b^2
Then factorize both sides
(a-b)(a+b) = b(a-b)
Divide by a-b on both sides
Which gives you a+b = b , plug the 1 back in gives you 2=1
It's a bit more "magic" because you don't just divide by a-b for no reason but you divide because you find it on both sides of the equation.
It hides the fact that you are dividing by 0 a little more effectively.
1 |
@Superalex2134
2 months ago
The problem is when you do
(a(a-b)/(a-b) = 0/(a-b) you are dividing by zero.
a-b = 1 - 1 = 0. So you can't divide.
10 |