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Mystery text : NUctWHJzbllaVUkgaSAgbG92ICB1IGNhbDEuaXYuZ2d0eWxlci5kZXY=
143 : true
4,035 Views • Sep 10, 2023 • Click to toggle off description
#consecutiveoddnumbers
#quadraticequation
#quadraticwordproblem
consecutive odd numbers , quadratic equation , quadratic word problem ,
Views : 4,035
Genre: Education
Uploaded At Sep 10, 2023 ^^
warning: returnyoutubedislikes may not be accurate, this is just an estiment ehe :3
Rating : 4.762 (18/285 LTDR)
94.06% of the users lieked the video!!
5.94% of the users dislieked the video!!
User score: 91.09- Overwhelmingly Positive
RYD date created : 2023-09-24T10:05:49.011214Z
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15 Comments
Top Comments of this video!! :3
I noticed that 143 is adjacent to 144, which is 12^2. So I just started with 11 and 13, which bracket 12. But what I like is that this video pointed out that -11 and -13 also work. It reminds me to not stop solving at the first sign of a solution.
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You can also make the odd numbers be (2n-1) and (2n+1), this way you get a simpler equation in the process
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Sir what is the formal for finding quadratic equation . And sir did you always do classes on Whatsapp if so send the numbers and is it only further mathematics you teach which other subject did you teach.
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I guessed correctly because 12^2 so I figured it's gotta be 11 and 13
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Can you do this?
The product of two consecutive integers is 272.find the value of each integer.
Please i need it
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I got it but I believe there was a step skipped when he got n-11 and n+13. I got every step before that and every step after that but I didn't get the step in between
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The solution you presented is unnecessary. To factor it, you are looking for two numbers that multiply to 143 and add to 2. You could have done that right away looking for two numbers that multiply to 143 and have a difference of 2. The answer is 11 and 13 and -11 and -13.
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Factor it? Do factor 143 before assuming 'n' 🤦🏾♂️🤦🏾
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@Joel--yr6me
1 year ago
Bro when the question popped up I guessed 11 and 13 and I was right!
Your way works better but that was cool man
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